[quote=&quot;PLA&quot;:lrtn0kiv]
Come &quot;suggerimento&quot; brutale della serie stessa.. mi sembrava una buona idea, in quanto mi portava al limite per confronto asintotico:

[tex:lrtn0kiv]\displaystyle\lim_{n \to \infty}&#40;\frac{\sqrt[n]{n}-1}{\sqrt[n]{n}}&#41;^2=1[/tex:lrtn0kiv]
[/quote:lrtn0kiv]

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